3(x^2+4)=2x^2+17

Solution for 3(x^2+4)=2x^2+17 equation:

Simplifying
3(x2 + 4) = 2x2 + 17

Reorder the terms:
3(4 + x2) = 2x2 + 17
(4 * 3 + x2 * 3) = 2x2 + 17
(12 + 3x2) = 2x2 + 17

Reorder the terms:
12 + 3x2 = 17 + 2x2

Solving
12 + 3x2 = 17 + 2x2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2x2' to each side of the equation.
12 + 3x2 + -2x2 = 17 + 2x2 + -2x2

Combine like terms: 3x2 + -2x2 = 1x2
12 + 1x2 = 17 + 2x2 + -2x2

Combine like terms: 2x2 + -2x2 = 0
12 + 1x2 = 17 + 0
12 + 1x2 = 17

Add '-12' to each side of the equation.
12 + -12 + 1x2 = 17 + -12

Combine like terms: 12 + -12 = 0
0 + 1x2 = 17 + -12
1x2 = 17 + -12

Combine like terms: 17 + -12 = 5
1x2 = 5

Divide each side by '1'.
x2 = 5

Simplifying
x2 = 5

Take the square root of each side:
x = {-2.236067978, 2.236067978}